data hw 3 - region so the best answer is reject the null...

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Question 1 1) First what I did was standardize x bar and solved for it and got that the sample mean is 5076.5 which was not in the rejection region. Then I did the standardized test statistic and took .05 which is 1.645 and solved for Z value of 1.4 which is not in the rejection region, so I reject the alternative. 2 )I standardized x bar and got 578.4 and it was not the in the rejection region. Then I did the standardized test statistic and alpha, which was 1.645 and solved for Z and the got .805, which is also not in the rejection region, so I have enough evidence to reject the alternative. 3) first what I did was standardized the x bar and got 55.79 which is really close to 55.8 the sample average and Is barely outside of the rejection region. Next I did the test standardized test statistic and solved for Z and got .011 which is barely in the rejection
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Unformatted text preview: region so the best answer is reject the null hypothesis. 4) First what I did was standardize x bar and used 2.235 as the Z value because alpha was .01 then found that x bar equaled 105.65 and the sample mean is just inside the rejection region which is 105.7. Lastly, I Standardized for Z and found that Z equaled 2.253 which is inside of the rejection region, so there is enough evidence to reject the null hypothesis. 5) This question was a little confusing because of the negative numbers so I plotted everything on the negative side. First I standardized x bar and got 5.512 which is below the average. Then I standardized Z and got 1.6 and that is smaller than 1.28 and got 1.6 which is in the rejection region so I have enough evidence to reject the null....
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This note was uploaded on 04/30/2008 for the course WCOB 1023 taught by Professor Sandeepgoyal during the Spring '08 term at Arkansas.

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