Unformatted text preview: v 1 = a 2 , 3 , − 1 A , and L 2 is parallel to the vector v 2 = a 1 , 1 , 3 A . Since these vectors are not parallel, it follows that L 1 and L 2 are not parallel. To see whether they intersect, we need to ±nd a solution (if any) to the linear system: 1 + 2 t = − 1 + s, 3 t = 4 + s, 2 − t = 1 + 3 s. Solving the ±rst two equations for t and s yields t = 6 and s = 14. But the third equation is not satis±ed, so we conclude that this system has no solution. Therefore the lines are skew (ie, they do not intersect)....
View Full Document
This note was uploaded on 04/29/2008 for the course MATH 20C taught by Professor Helton during the Spring '08 term at UCSD.
- Spring '08