This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: x = 1 3 ± r29 9 = 1 3 ± √ 29 3 i. (2) (a) Please sketch the area enclosed by the polar curve r ( θ ) =  sin θ  . (3 points)21.510.5 0.5 1 1.5 21.510.5 0.5 1 (b) Please compute the area of the ‘ﬂower’ described by the polar curve r ( θ ) = 5sin(7 θ ). (3 points)107.552.5 2.5 5 7.5 1052.5 2.5 5 We use the formula for the area enclosed by a polar curve: 1 2 Z 2 π (5sin(7 θ )) 2 dθ = 1 2 Z 2 π 2510 sin(7 θ ) + sin 2 (7 θ ) dθ = 1 2 ± 25 · 2 π + 10 7 cos(7 θ )  2 π + 1 2 Z 2 π 1cos(14 θ ) dθ ² = 1 2 ± 50 π + 1 2 · 2 π1 28 sin(14 θ )  2 π ² = 51 2 π 2 Good Luck! 3...
View
Full
Document
This note was uploaded on 04/29/2008 for the course MATH 20B taught by Professor Justin during the Fall '08 term at UCSD.
 Fall '08
 Justin
 Math

Click to edit the document details