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Unformatted text preview: 2resistor: I = 12V 4 = 3A . (b) No current through capacitor: I = 12V 6 = 2A . tsl353 p.3/4 Intermediate Exam II: Problem #4 (Spring 06) A current loop in the form of a right triangle is placed in a uniform magnetic field of magnitude B = 30 mT as shown. The current in the loop is I = 0 . 4 A in the direction indicated. (a) Find magnitude and direction of the force ~ F 1 on side 1 of the triangle. (b) Find magnitude and direction of the force ~ F 2 on side 2 of the triangle. 20cm 20cm 3 1 2 B Solution: (a) ~ F 1 = I ~ L ~ B = 0 (angle between ~ L and ~ B is 180 ). (b) F 2 = ILB = (0 . 4A)(0 . 2m)(30 103 T) = 2 . 4 103 N . Direction of ~ F 2 : (into plane). tsl354 p.4/4...
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This note was uploaded on 04/30/2008 for the course PHYSICS 204 taught by Professor Dr.steryl during the Fall '07 term at Rhode Island.
 Fall '07
 Dr.steryl
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