Chem 112 Lab 1 Report - H20 and 5ml of ethanol, and...

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Lab 1 Report Procedure: 1)Weighed 5.022g of Fe(NH 4 ) 2 (SO 4 ) 2 * 6H 2 O in an Erlenmeyer flask, dissolve in 15ml of H 2 O 2)Added 4 drops of H 2 SO 4 of 3M concentration 3)Added ~50ml of 0.5M H 2 C 2 O 4 4)Heated until almost boiling and removed when the yellow precipitate formed 5)Waited until the precipitate settled and removed the liquid with a pipet. Then we added ~10ml of H 2 0 at a high temperature and re-extracted the liquid with a pipet. 6) Added 30ml of ~1M K 2 C 2 O 4 and heated to 48oC 7)Added 10ml of 6% H 2 O 2 at 48oC and the solution turned brown, heat to boiling 8) Added ~0.5M H 2 C 2 O 4 until the solution turned green 9) While stirring, added 15ml of ethanol to the solution 10) Put in an ice bath, let sit for 20 minutes, or until crystals settle 11) Prepared vacuum apparatus, vacuum – filtered the solution, and then added 5ml of
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Unformatted text preview: H20 and 5ml of ethanol, and re-filtered the crystals. Data: 5.002 of Fe(NH 4 ) 2 (SO 4 ) 2 * 6H 2 O To 2.638 of K 3 [Fe(C 2 O 4 ) 3 ] * 3 H 2 O Calculations: 5.002g / 392.1g/mol = 0.012757 mol Fe(NH 4 ) 2 (SO 4 ) 2 * 6H 2 O 2.638g / 491.1g/mol = 0.005372 mol K 3 [Fe(C 2 O 4 ) 3 ] * 3 H 2 O 0.012757mol 0.005372 mol = 0.007385 mol Conclusion: In this lab we reacted Fe(NH 4 ) 2 (SO 4 ) 2 * 6H 2 O the with excess reactants, and we maintained the number of moles of the product from one reaction to the next. We ended up losing 0.007385 moles of the product to inefficient lab techniques. These would include the filter, the precipitate not completely falling out of solution, the inconsistent heat of reaction, and even an over boiling (bumping)....
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This note was uploaded on 04/30/2008 for the course CHEMISTRY 112 taught by Professor Whelan during the Spring '08 term at UMass (Amherst).

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Chem 112 Lab 1 Report - H20 and 5ml of ethanol, and...

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