Chem 112 Lab 2 Report - 4 = .021 0.0043 x .021 = 9e-5...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Lab 2 Report Data: C 2 O4 2- Analysis Sample 1 Sample 2 1)Molarity of KMnO 4 .021 .021 2)Weight of Sample .217 .220 3)Final Buret Reading 50.00 33.20 4)Initial Buret Reading 20.00 0.00 5)Volume of KMnO 4 dispensed 30.00 33.20 6)Moles of KMnO 4 .700 .6325 7)Moles of C 2 O4 2- .280 .253 8)Final Buret Reading (2 nd ) 34.30 44.50 9)Initial Buret Reading (2 nd ) 30.00 40.00 10)Volume 4.30 4.50 Calculations: 1) Calculate the moles of C 2 O4 2- present from the molarity and volume of KMnO 4 solution Sample 1: Volume = 30ml, Molarity of KMnO 4 = .021 0.021 x .03L = 6.3e-4 mol/L (6.3e-4) ( 5/2) = 0.001575 moles Sample 2: Volume = 33.2ml, Molarity of KMnO 4 = .021 0.021 x .0332 = .000697 moles/L (6.97e-4)(5/2) = 0.001743 moles 2) Calculate the moles of Fe 3+ present Sample 1: Volume = 4.30ml, Molarity of KMnO
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 4 = .021 0.0043 x .021 = 9e-5 (9e-5)(5) = 4.52e-4 Sample 2: Volume 4.50ml, Molarity of KMnO 4 = .021 .0045 x .021 = 9.5e-5 (9.5e-5)(5) = 4.73e-4 3) Find: Ratio of C 2 O4 2- / Fe 3+ Sample 1: .001575 mol / 4.52e-4 mol= 3.48 Sample 2: .001743 mol /4.73e-4 mol = 3.68 Discussion: We obtained a 3.58 average ratio of C 2 O4 2- to Fe 3+ ions. This is consistent with the expected 3:1 ration in the original formula of K 3 [Fe(C 2 O 4 ) 3 ] * 3 H 2 O where the ratio is 3 to 1. The inconsistency might have arose from the incomplete reaction with zinc, because the zinc was still reacting when I took it off the burner....
View Full Document

This note was uploaded on 04/30/2008 for the course CHEMISTRY 112 taught by Professor Whelan during the Spring '08 term at UMass (Amherst).

Page1 / 2

Chem 112 Lab 2 Report - 4 = .021 0.0043 x .021 = 9e-5...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online