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Unformatted text preview: and/or cc genotypes. Looking at the list above, there are 37/64 colorless genotypes. 27 : 37 is the ratio of the colorless individuals in the F2 progeny. B) In order for an individual to be black, it must be normal at the A and B allele, but not at the C allele, or A-/B-/cc. If the inhibitor allele is normal, it will prevent the production of the black color, therefore, it must be recessive. Looking at the list above, there are 9/64 such genotypes. The rest of the genotypes (1 – 9/64 = 55/64) must then be colorless. A 9 black: 55 colorless ratio is expected in the F2....
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- Spring '08
- Genetics, Ratio, aabbcc