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Unformatted text preview: involved. We can assume that: Wild Type A_B_ Platinum aaB_ or A_bb (Assume A_bb) Aleutian A_bb or aaB_ (Assume aaB_) Sapphire aabb When pure lines of the above genotypes are crossed in Cross 1,2,and 3, the F1 and F2 progeny genotype ratios match those shown in the problem table, proving the assumed genotypes to be true. 2) aabb x AAbb (sapphire x platinum) F1: all Aabb (all platinum) F2: Aabb aabb ( platinum sapphire) 3:1 aabb x aaBB (sapphire x Aleutian) F1: all aaBb (all Aleutian) F2: aaBb aabb ( aleutian sapphire) 3:1...
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This note was uploaded on 04/30/2008 for the course BIOLOGY 282 taught by Professor Barlow during the Spring '08 term at UMass (Amherst).
- Spring '08