317L_ex2_F07 - Anew-fer the following questions: i. A....

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Unformatted text preview: Anew-fer the following questions: i. A. parallel plate capacitor is charged up by a batter}r and then disconnected. Suppose the plates are then pulled apart to some separation greater than the original gap e: between the plates. in the process of pulling the plates further apart, what happens? fil‘he stored energyr in the capacitor increases. % 69 P' {hi The stored energj,r in the capacitor clccreascs. '— {c] The voltage across the capacitor decreases. {cl} The capacitance increases. 4‘4:- gfgsfir‘ =3 C ‘4' Int-LIL [ej The charge on the capacitor decreases. =$ a *3- 555w— 2. in the diagrams: all the light bulbs are identical end all EMF devices are identical. In which circuit {Pa D. C, D: E) will the bulbs glenr with the same brightnms as in circuit X? _| I-.. _| H ._| H .__,.. F P : '2‘ e; = if; on i @336; a) c T [j iii fl w—FE‘P E U2 -" “1 )1 ®P1._:K:fize - @P:t¢a: 5E Its—MHJ (9 P: P:'L‘E‘_-_-_ (9 P: Leg: use“: Etfivjfi 3. Four wires meet at a junction. The first carries 4 it into the junction. the seconcl carries 5 A. cut of the junction. and the third carries 2 it out of the junction. The fourth carries {a} T A out of the junction ‘1' t 411 {bl 7 Pi into the junction 24 E a {c 3 A out of the junction in. 1‘ r-Ii'o A into the junction 15' A ., (e) 1 A into the junction 4. A hatter},r is connected seress s. n pnrellel combination of two identical resistors. 1f the potential difference across the terminals of the battery is V and the current in. the battery is i! then: in] the potential difference across each resistor is V, tho current. in eseh resistor is 1'. {hi the potential difference across each resistor is WE, the current in each resistor is 1'32. f, {e} t . potential diflerence across each resistor is V, the current in eseh resistor is #2. id} the potential difierenee across eseh resistor is VIE, the current in each resistor is i. (e) none of the shove are true. V f If E 5. The equivalent- resistsnee between points 1 end 2 of the circuit. is: is} 3 51 1e 1e ‘ '3‘ {s} 4 o 1 J2. {s} so r n 2 lel so so f =23. ti. In the diagram, the current in the 3 fl resistor is 4 A. The voltage difference between points 1 and 2 is: {a} ere V {s} use 1: 1.__._._.._n—illxii,—:~.i"~iit—-2 {C} 1.25 v (d - tr 3: 447* t: 44—3 «fire ' V '6 . 51/1 til? it ém>(§£) = Zoe T. In an antique ant:iniohilc1 a F: V ha;1.’t.ter.‘;i,r supplies a total of :18 ‘N to two identical headlights in parallel. The resistance {in ohms] of each bulb is: I. (a) are 51 f9: a) .5 a {mine 2 (‘1’ _ __ U “m a 24wieeacca Ag“? inky“; R1,? 1-. £93 3. Each of two 25 pF capacitors shown is initiallyr uncharged. How many coulomhe of charge pass through the amineter A after the ewitch S is closed? [ainm E . U c) 10 S . I i = 2:: La} one U = 4mm v l c I t: [ci none of these .3 gar F a? = C u 1 r? :(QarFflaooU) : éX{ahg_iL_)(’i/x.fd V) 4‘ 20;: no fear 9. Capacitors A and F} are identical. Capacitor A is charged so it stone; 4 .l of energy and capacitor H is uncharged. The capacitors are then connected in parallel. The total stored energy in the capacitors. is now: ‘2 (3.} 1a.] 1 . ‘ :__ C? {1133.1 M'lmll'l’ a: 2g; {-3 .i .2 J ‘ (:3 am: .I my M— x (.a. a J {e‘J lJ U 2* J; fail: éemllel) 4 1 idol It]. A dielectric slab is slowlgrr inserted between the plates of a parallel plate capacitor, while the potential difference between the plates is held constant by a battery. As it is being inserted, {a} the capacitance, potential difference between the plates, and charge on the positive plate all increase. {h} the capacitance, potential difference between the plates, and charge on the positive plate all decrease. to] the potential difference between the plates increases, the charge on the positive plate decreases, and the capacitance remains the same. {d} the capacitance and charge on the positive plate decrease, but the potential differ— ence between the plates remains the same. e) e eapaeitanoe and charge on the positive plate increase, but the potential differ- ence between the plates remains the same. 11. An electron moves in the negative ,‘L' direction, through a uniform magnetic field in the negative 3; direction. The magnetic force on the electron is in which direction? {a} in the negative :1: direction it? i: fi x E [b] in the positive y direction ? {c} in the negative y direction {2 [5 Mj AFIUL {d} ' the positive 2 direction - the negative 2: direction x EsqLFB(—£K ‘5) :cicr'Ee‘E. {EMR'fI—flw 12. The diagram shows a straight wire carrying positive current i. The wire is in a region of externally—supplied nniforrn magnetic field. The force on the wire is indicated by an arrovir but the magnetic field is not shown. Of the following possibilities, the direction of the magnetic field is: _ 1. {a] opposite the direction of the current 3 [b] opposite the direct-ion of the force l (c) in the direction of the force “I'll .-iI-. ,A. “M Fr—ILYE (d into the page out of the page in 13. Two parallel long wires carrg,r the same amount of current and attract each other with a force F per unit length. H both these currents are doubled and the wire separation halved1 the force per unit length becomes: _L dis {a} so F = Ill. X 9: .. ‘ “,3 1.“ L I .2 l I {s} as [d] 41: [(EJ:ILL¢:I llI it; -; ‘Eorce: fir iMIlv't 4" 73,) “(I’m-c: Anne‘s-ii. '%I$l ——‘:~ 3’ IF“) M. It solenoid is 3.1) cm long and has a radius of 0.543 cm. it is wrapped with SDI] turns of wire carrying a current of 2.1] A. The magnitude of the magnetic field at the center of the solenoid is: 1 .. we I. {a} as x nil-*-1 Tesla B - (“D {s} is x 10-3 Tesla M . J" {as _ .. '= .— T E” (a: {in ""7 @x10 2 lesla (an L r T and M j: is Tesla 2 (e) an Tesla '3 3 Fe .7: 43 (£1 k r: — F—x (a Y“: —‘ no {dill 3 3 15. A long straight wire is in the plane of a rectangular conducting loop. The straight wire .earrles a constant current i. as shown. While the wire is being moved toward the loop, the current in the rectangular loop is: (a) com (in) clockwise yllflhflrfllflflkwlfifi d} clockwise in the left side and counterclockwise in the right side is) counterclockwise in the left side and clockwise in the right side 1: r ‘15- C’flmnr'l'U‘ flffiflabfl-isc iti. 1'r'ou push a perrusnenl. her magnet with its north pole away from you toward a loop of conducing 1:Irire in front of you. Before the north pole. enters the loop, the current in the loop is: {a} zero __ m ‘ rib clockwlse g M Eb { I: ountercioei-iwise '3 :1} to your left a (e) to your right I For: Jet»: dam-46L to? it,»th IT. A square loop of 1wire moves with a constant speed v from a, field—tree region into a region of constant uniform magnetic field1 as shown. 'Which of the five graphs correctlyr shows the induced current 1' in the loop as. a function of time I? 135. The diagrams show three circuits with identical batteries, identical inductors, and iden- tical resistors. Brink them according to the current through the better}.r just efier the switch is closed. going from least to greatest. ‘ u h it; = I, :-‘ u-' {a} s, 2, 1 “n 71‘- ‘: 2 [h] 2 end 3 tie1 then i t «it d}1,2,3 t_./| {e} 3,1,2 {34’ 'L? O JrEx-I maimed”— Gfii'fl- hilt!!— dm agree. 19. ft ecrics HL circuit is connected tn an emf euurce nf angular frequency w. The current: {:91 ads the applied emf by tam—lituLg'R] [1:- '1 the! applied emf by ten—liij'l-i.) XII— Hf: {c} lugs the applied emf by ten-1 (wilij Aunt? F—R : :- I::1} leads the applied emf by ten Well-UL) {c} is zcrc / XL CY: :_ a I 3 2f]. A circuit has a. resistance cf 3D [2 and an inductive reectunce 0f 4|] it. When newered by a. source of emf with maximum voltage 601] V, the maximum current is: [a] E A. {h} ee A a if t (/33: 2;: M at (rt—X3) (e) ‘20 A '7 C3551)1 + @gQ)-L (re: : O .i j @m‘ =€5E ...
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This note was uploaded on 04/30/2008 for the course PHY 317L taught by Professor Ritchie/lang during the Fall '08 term at University of Texas at Austin.

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317L_ex2_F07 - Anew-fer the following questions: i. A....

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