takehometest

Takehometest - μ 1 mean of 1 Temperature μ 2 mean of 2 Temperature μ 1 μ 2 mean difference H μ 1 μ 2 = 0 H A μ 1 μ 2 0 ≠(without pooled

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Take Home Test Problem 2 1. Both histograms are normally distributed. There are no outliers. 2. Summary statistics: Colu mn n Mean Varia nce Std. Dev. Std. Err. Medi an Rang e Min Max Q1 Q3 Male Temp 65 98.10 4614 0.488 2596 0.698 75574 0.086 66999 98.1 3.2 96.3 99.5 97.6 98.6 Femal e Temp 65 98.39 3845 0.552 774 0.743 4878 0.092 21831 98.4 4.4 96.4 100.8 98 98.8 For males, the observed sample mean is 98.104614 and the standard deviation is .69875574. For females, the observed sample mean is 98.393845 and the standard deviation is .7434878.
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3. Hypothesis test results:
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Unformatted text preview: μ 1 : mean of 1 Temperature μ 2 : mean of 2 Temperature μ 1- μ 2 : mean difference H : μ 1- μ 2 = 0 H A : μ 1- μ 2 0 ≠ (without pooled variances) Difference Sample Mean Std. Err. DF T-Stat P-value μ 1- μ 2-0.28923076 0.12655395 127.5103-2.2854345 0.0239 The p-value is < .05, which means we reject the null hypothesis, H : μ 1- μ 2 = 0, and conclude there is evidence that the mean body temperature is different for males and females....
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This note was uploaded on 04/30/2008 for the course MATH 143 taught by Professor L.kapitula during the Spring '08 term at Calvin.

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Takehometest - μ 1 mean of 1 Temperature μ 2 mean of 2 Temperature μ 1 μ 2 mean difference H μ 1 μ 2 = 0 H A μ 1 μ 2 0 ≠(without pooled

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