SampleEx3S - Chem 6 sample Exam 3 solutions 1. (a) CO, (c)...

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Chem 6 sample Exam 3 solutions 1 . (a) CO , (c) BrF 3 , BBr 3 , like BF 3 , is trigonal planar and the B-Br bond dipoles cancel out. The same is true for trigonal bipyramidal PF 5 . Linear CO has a dipole moment since C and O have different electronegativities. BrF 3 is a distorted T-shape, and the bond dipoles don't cancel out. XeF 4 is square planar, and the bond dipoles cancel out. 2 . (a) O 3 has a structure based on the trigonal plane, since there are 2 oxygens and 1 lone pair on the central O. O O O : : : + O O O : : + Therefore, its idealized geometry is bent with an O-O-O angle of 120°. Again a distortion is expected because of the lone pair on O, to make the angle <120°. (b) BrF 5 has a structure based on an octahedron, with 5 Br-F bonds and one lone pair on Br. 90° 90° F Br F F F F lone pairs shown only on one F Its idealized structure is a square pyramid , but to avoid repulsion from the lone pair, it will distort such that the bond angle F square-plane -Br-F axial is less than the ideal 90°. 3 . (a) GaCl 4 : this has 32 valence electrons, and its structure is based on tetrahedral geometry at Ga (4 electron pairs around the central atom). It is
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therefore tetrahedral (like CH 4 ). SbCl 4 has 34 valence electrons, and its structure is based on trigonal bipyramidal geometry at Sb (5 electron pairs around the central atom). The lone pair goes in an equatorial position, so the structure is a distorted see-saw like SF 4 .
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SampleEx3S - Chem 6 sample Exam 3 solutions 1. (a) CO, (c)...

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