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Unformatted text preview: y ( x ) 1, but that is not the solution that you want here. Since the equation is separable, you have Z 1 1y dy = Z 1 dx, andln  1y  = x + C. Since y (0) =1, that means that C =ln2. So  1y  = ex +ln 2 = 2 ex , and y = 12 ex . b) Find the solution to the equation in part a) satisfying y (0) = 1. Solution. This is the equilibrium solution y ( x ) 1....
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 Spring '07
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 Differential Equations, Equations

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