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Unformatted text preview: F ( x,y ) = Z ( x 2 + 2 xy ) dx + h ( y ) = x 3 / 3 + x 2 y + h ( y ) F y = x 2 + h ( y ) So we need h ( y ) = y 2 , which gives h ( y ) = y 3 / 3 + C and F ( x,y ) = x 3 / 3 + x 2 y + y 3 / 3 + C. b) The level curves of the function F ( x,y ) that you found in part a) are solutions to a rst order dierential equation. Write down that dierential equation. Solution . We have = 0 when y = y ( x ) is a solution to the dierential equation. So 0 = ( x 2 + 2 xy ) dx + ( x 2 + y 2 ) dy dx dx = [( x 2 + 2 xy ) + ( x 2 + y 2 ) dy dx ] dx So the dierential equation is 0 = ( x 2 + 2 xy ) + ( x 2 + y 2 ) dy dx or in normal form dy dx =x 2 + 2 xy x 2 + y 2 . Of course, you could get that just by setting = 0, dividing by dx and then solving for dy dx . That dividing by dx step does not make sense, but the notation is designed so that it leads to the right answer!...
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 Spring '07
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 Differential Equations, Equations

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