Solution_Set_01b

# Solution_Set_01b - Physics 2022 Spring 2008 1 1.4 x 1011 cm...

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SOLUTION SET 1 Physics 2022 – Spring 2008 1. 1.4 x 10 11 cm / 30 cm = (4.2 ly) (9.46 x 10 17 cm/ly) / d d = 8.5 x 10 8 cm = 8.5 x 10 3 km 2a. d = 1.496 x 10 8 km / 9.46 x 10 12 km/ly = 1.58 x 10 -5 ly 2b. d = 1.496 x 10 8 km / [ (606,265 AU/pc) (1.5 x 10 8 km/AU)] = 4.85 x 10 -6 pc 2c. No -- too small 3. d = c t = (3 x 10 5 km/s) (4 hr) (3600 s/hr) = 4.3 x 10 9 km 4a. d = (3.50 pc) (3.09 x 10 13 km) / (1 pc) = 1.08 x 10 14 km 4b. d = (3.50 pc) (3.26 ly/pc) = 11.4 ly so it takes 11.4 years 5. t = 14 x 10 9 years x 365.25 days/year x 24 hr/day x 60 min/hr x 60 sec/min = 4.42 x 10 17 seconds 6. It is the number of arcseconds in one radian (= 57.29 degrees). 7. a) D = d sin θ d = 0.026/2 m / sin (0.5 deg) = 1.5 m b) D = d sin θ d = 0.026/2 m / sin (0.5 deg / 60) = 89 m c) D = d sin θ d = 0.026/2 m / sin (0.5 deg / 3600) = 5360 m 8. a) θ = 1.4 deg (x 60 arcmin/deg) = 84 arcmin b) θ = 1.4 deg (x 60 arcmin/deg x 60 arcsec/arcmin) = 5040 arcsec 9. It rises 4 minutes earlier each day, so in one week it rises 7 x 4 = 28 minutes sooner,

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Solution_Set_01b - Physics 2022 Spring 2008 1 1.4 x 1011 cm...

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