Takenote7 - c 1 mole of O = 15.9994 g/mole Compound has 1...

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Unformatted text preview: c. 1 mole of O = 15.9994 g/mole Compound has 1 mole of 0; therefore it has 15.994 grams of 0 (1. So the molecular weight of the compound = 24 + 6 + 16 2 46 e. % C by weight = (24 / 46) * 100% = 52 % f. % H by weight: (6/46) * 100% =13 % g. % O by weight: (16 /46) * 100% = 35 % C. With reference to the experiment demonstrated in class: 1. Al (5) + Br; (g) —p AlBr3 (s) a. This equation is unbalanced. b. So we balance it and the equation becomes 2 Al (s) + 3 Br; —> 2 A1133 2. % composition ofA1= | 27 ] * 100% = 10.1 % 27 + (3 * 39) ' 3. Aluminum foil is coated at the edges with aluminum oxide. So for bromine to react with aluminum it has to first act with aluminum oxide and hence there is 30- 40 secs delay in the reaction (delay in the vapors to come)...
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