IE360%20HW6%20solutions

IE360%20HW6%20solutions - IE 360 Homework Assignment #6...

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IE 360 Homework Assignment #6 Solutions 8-44 8-50 a only 9-36 a only 9-53 a & b only 9-54 a only 9-70 9-73 9-80 9-86 a only 9-89 a only ** Note : several of the Chapter 9 questions ask you to find a P-value – you can skip this part of the question. You do not need to find P-values. 8-44 95% confidence interval for σ 99 . 15 41 = = s n 34 . 59 2 40 , 025 . 0 2 1 , 2 / = = χ α n and 43 . 24 2 40 , 975 . 0 2 1 , 2 / 1 = = n 46 . 20 13 . 13 633 . 418 35 . 172 43 . 24 ) 99 . 15 ( 40 34 . 59 ) 99 . 15 ( 40 2 2 2 2 < < σ The data don’t appear to be normally distributed based on examination of the normal probability plot below. Therefore, there is not enough evidence to support that the time of tumor appearance is normally distributed. So the 95% confidence interval for σ is invalid. TimeOfTumor Percent 140 120 100 80 60 40 99 95 90 80 70 60 50 40 30 20 10 5 1 Mean <0.005 88.78 StDev 15.99 N4 1 AD 1.631 P-Value Probability Plot of TimeOfTumor Normal - 95% CI
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8-50 a) 95% Confidence Interval on the death rate from lung cancer. 823 . 0 1000 823 ˆ = = p 1000 = n 96 . 1 2 / = α z 8467 . 0 7993 . 0 1000 ) 177 . 0 ( 823 . 0 96 . 1 823 . 0 1000 ) 177 . 0 ( 823 . 0 96 . 1 823 . 0 ) ˆ 1 ( ˆ ˆ ) ˆ 1 ( ˆ ˆ 2 / 2 / + + p p n p p z p p n p p z p 9-36 a.) 1) The parameter of interest is the true mean water temperature, μ . 2) H 0 : μ 100 3) H 1 : μ < 100 4) α = 0.05 5) z x n 0 = −μ σ / 6) Reject H 0 if z 0 < -z α where z 0.05 = 1.645 7) 98 = x , σ = 2 0 . 3 9 / 2 100 98 0 = = z 8) Since -3.0 < -1.645 we reject H 0 and conclude the water temperature is acceptable since we believe it is less than 100 o F at α = 0.05. 9-53 a) 1) The parameter of interest is the true mean sodium content, μ .
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This note was uploaded on 05/01/2008 for the course IE 360 taught by Professor Chen during the Spring '08 term at University of Louisville.

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IE360%20HW6%20solutions - IE 360 Homework Assignment #6...

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