hw1sol - 2-142-3810! = 3,628,8002-48 a) The total number of...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2-142-3810! = 3,628,8002-48 a) The total number of possible samples is There are 220 ways to sample 3 parts from 12.The number of samples that result in 1 nonconforming part (and 2 conforming parts) is Therefore, the requested probability is 90/220 = 0.409.b) The number of samples with no nonconforming part is The probability of at least one nonconforming part is 1.2-62a) P(A) = 86/100 = 0.86b) P(B) = 79/100 = 0.79c) P(A') = 14/100 = 0.14d) P(AB) = 70/100 = 0.70e) P(AB) = (70+9+16)/100 = 0.95f) P(AB) = (70+9+5)/100 = 0.842-96N = event heart failure due to natural causes P(N) = 0.87O = event heart failure due to outside causes P(O) = 0.13I = induced substance P(I|O) = 0.73F = foreign objects P(F|O) = 0.27A = arterial blockage P(A|N) = 0.56D = disease P(D|N) = 0.27E = infection P(E|N) = 0.17a)Find P(I) = P(I|O)P(O) = (0.73)(0.13) = 0.0949b)Find P(DUE) = P(D) + P(E) = P(D|N)P(N) + P(E|N)P(N) = (0.27)(0.87) + (0.17)(0.87) = 0.38282-110(a) Let X = number of opponents defeated in a game. (a) Let X = number of opponents defeated in a game....
View Full Document

Page1 / 4

hw1sol - 2-142-3810! = 3,628,8002-48 a) The total number of...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online