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# hw5s - EE 341 ENERGY CONVERSION Homework#5 Solutions 1 A...

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EE 341 – ENERGY CONVERSION 1 Homework #5 Solutions 1. A 100-kVA, 240/120-V Y-Y three-phase power transformer has a per-unit resistance of 0.01 pu and a per-unit reactance of 0.035 pu. The excitation branch elements are R C = 80 pu and X M = 20 pu. (a) If this transformer supplies a rated load at 0.8 PF lagging, draw the phasor diagram of one phase of the transformer. (b) What is the voltage regulation of the transformer bank under these conditions? (c) Sketch the equivalent circuit referred to the low-voltage side of one phase oh this transformer. Calculate all the transformer impedances referred to the low-voltage side. Solution: Select kVA S base 100 = , V V base P 240 , = , V V base S 240 , = (a) pu S o load 87 . 36 0 . 1 ) 8 . 0 ( cos 0 . 1 1 = = - o S V 0 0 . 1 = pu V S I o o o S load S 87 . 36 0 . 1 0 0 . 1 87 . 36 0 . 1 * * - = = = pu j Z I V V o o o eq S S P 225 . 1 0292 . 1 ) 035 . 0 01 . 0 ( 87 . 36 0 . 1 0 0 . 1 = + - + = + = The phasor diagram is shown as below: (b) The voltage regulation under these conditions is: % 92 . 2 % 100 0 . 1 0 . 1 0292 . 1 % 100 , , , = × - = × - = fl S fl S nl S V V

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hw5s - EE 341 ENERGY CONVERSION Homework#5 Solutions 1 A...

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