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hw8 - There are several ways of solving this problem 5 Note...

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Keep the ideas below in mind when working these problems. 1
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Chapter 4, Problem 40. Find the Thevenin equivalent at terminals a-b of the circuit in Fig. 4.107. Figure 4.107 For Prob. 4.40. To obtain V Th , apply KVL to the outer loop, find loop current, and then V ab . Find R th using one of the methods listed. 2 + _ 70 V + V o 4 V o + 10 k 20 k b a
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Chapter 4, Problem 43. Find the Thevenin equivalent looking into terminals a - b of the circuit in Fig. 4.110 and solve for i x . The 6 ohm resistor is a load resistance. Figure 4.110 Note there are no dependent sources which simplifies this problem. 3
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Chapter 4, Problem 48. Determine the Norton equivalent at terminals a - b for the circuit in Fig. 4.115. Figure 4.115 The solution manual uses a test injection for this problem. Open circuit V and short circuit I may be a simpler. Try it and see. 4
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Chapter 4, Problem 51. Given the circuit in Fig. 4.117, obtain the Norton equivalent as viewed from terminals (a) a - b (b) c - d Figure 4.117 There are no dependent sources in this circuit, which makes the analysis simpler.
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Unformatted text preview: There are several ways of solving this problem. 5 Note that the 4 ohm and 2 ohm resistors are not treated as load resistors. Chapter 4, Problem 54. Find the Thèvenin equivalent between terminals a-b of the circuit in Fig. 4.120. Figure 4.120 The solution manual uses left and right loops to find the open circuit V at V ab . The R th can be found with a test injection on the output. Possibly short circuit I on the output could also be used to find R th . 6 + – Chapter 4, Problem 73. Determine the maximum power that can be delivered to the variable resistor R in the circuit of Fig. 4.139. Figure 4.139 The circuit has no dependent sources making the analysis simple. Once the Thevenin equivalent is determined, the maximum power to R is easily calculated. Treat R as a load resistance and not as a part of the Thevenin circuit. 7...
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hw8 - There are several ways of solving this problem 5 Note...

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