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Unformatted text preview: . But you must first work it using three loops. I1=i0, I2, I3 M U = K 12k 6k 4k I1 306k 14k 2k I24k 2k 10k I3 I1 = 30/7k I2 = I3 = Chapter 3, Problem 44. Use mesh analysis to obtain i o in the circuit of Fig. 3.90. Figure 3.90 IS = I2 + I3 I3I2 = 3 Io = I2 – I1 (look at their directions. I2 is going in the same direction, I1 is going in the opposite direction.) Do it just like #50 Chapter 3, Problem 50. Use mesh analysis to find the current i o in the circuit in Fig. 3.95. Figure 3.95 I1, I3 I2 IS = I3+I2 I3 – I2 = 3Io60 + 10(I2I1) + 2(I3I1) + 8I3 = 0 4I+ 2(I1I3) + 10(I1I2) = 0 Chapter 3, Problem 52. Use mesh analysis to find i 1 , i 2 , and i 3 in the circuit of Fig. 3.97. Figure 3.97 Vo = 2(I1I2) 2Vo = 2(2(I1I2)) = 4(I1I2) IS = I2 + I3 I3 – I2 = 3...
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 Fall '06
 MCCANN
 Mesh Analysis, Voltage drop, i2

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