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Unformatted text preview: (0.0005+0.005)(100) = 0.55 volts. 1 The silicon transistor has a 0.7 voltage drop from the base to the emitter. This means that the base is 0.7 volts greater than the emitter. Summing the 0.7 volts and the emitter 0.55 voltages gives the base voltage as 0.7+0.55 = 1.25 volts on the base. Knowing the base terminal has a voltage of 1.25 volts allows us to calculate the current through the 2000 ohm resistor as 1.25/2000 = 0.000625 A. The sum of the current through the 2000 ohm resistor and the transistor base lead is 0.000625+0.0005 = 0.001125 A. The R needed to give this current for a voltage drop of 12 to 1.25 volts is: (12 – 1.25) / 0.001125 = 9555 ohms or R = 10k ohms as a standard value. 2...
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This note was uploaded on 05/01/2008 for the course EE 302 taught by Professor Mccann during the Fall '06 term at University of Texas.
 Fall '06
 MCCANN
 Transistor, Volt

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