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EE302Lecture6

# EE302Lecture6 - Example Circuit Con’t What is the voltage...

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Example Circuit Con’t What is the voltage across element 2? 1.Define the voltage across element 2. 2.Choose a path. 3.Sum the voltage drops around the chosen loop – see below -5V + V 2 + 3V + 6V + 2 V = 0 V 2 = -6.00V 1

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Example Circuit Con’t Would the answer be different if we took another path? No. -5V + V 2 + V 4 + 2 = 0 From before, V 4 = 9V V 2 = -6.00 V Or the same result as before! 2
KVL Practice Problem 1 Compute the voltages associated with elements D, E and F as indicated. Show work so that V D =70, V E =200, and V F =50. Practice Problem 2 Compute the voltages associated with elements A, C, E and G as indicated. Write KVL equations showing how you get the following results: V A =-80, V C =120, V E =-40 and V G =-160. 3

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Concluding Remark The concepts we have covered are sufficient to solve all DC circuits. Ohm’s Law Kirchhoff’s Current Law KCL Kirchhoff’s Voltage Law KVL Next we will add additional concepts and methods to simplify their application. Series and Parallel Circuits Equivalent Resistance Voltage and Current Dividers Basics Concepts and Laws Basic Concepts Circuit Elements Ohm’s Law Kirchhoff’s Laws Series and parallel circuits Equivalent Circuits Resistors in series and parallel Current and voltage dividers Measuring current and voltage 4
Must obey the passive sign convention! V 1 + V 2 - 12 = 0 V 1 + V 2 = 12 The Single Loop Circuit Elements in a circuit which exclusively share a single node and hence carry the same current are in series . What is the series current, I S ? First, we need voltage references for the resistors. 5

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The Series Circuit Example What is the series current I S ? From KVL: V 1 + V 2 = 12 Invoke Ohm’s Law: V 1 = I S R 1 V 2 = I S R 2 Then substitute: I S R 1 + I S R 2 = 12 I S (R 1 + R 2 ) = 12 I S = 12/(R 1 + R 2 ) What is the power absorbed by each circuit element?
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