061Exam2asoln

061Exam2asoln - EXAM 2 Section xxx March 2 2006 NAME Note...

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EXAM 2 Section xxx March 2, 2006 NAME: Note that to receive full credit on the short answer questions, relevant work and a correct answer must be shown. An incorrect answer with correct work for the problem shown can receive partial credit. A correct answer with no work shown can receive no credit. Good luck!! “On my honor, as a University of Colorado at Boulder student, I have neither given nor received unautho- rized assistance on this work.” YOUR SIGNATURE: 1. (6 points) Find the equation of the tangent line to the curve f ( x ) = (5 x 2 - 5 x - 2)( - 4 x + 1) at the point x = 0. Solution: f (0) = (5(0 2 ) - 5(0) - 2)( - 4(0) + 1) = - 2. Di±erentiating to ²nd the slope at x = 0 gives f ( x ) = - 4(5 x 2 - 5 x - 2)+( - 4 x +1)(10 x - 5), so f (0) = - 4(5(0 2 ) - 5(0) - 2)+( - 4(0)+1)(10(0) - 5) = 3. So an equation of the line tangent to f ( x ) at x = 0 is y = 3 x - 2. 1
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2. Derivatives (2 points each) For each question, fnd the derivative o± the indicated ±unction and choose the single best answer. The problem will be graded as right or wrong, so no work is required to receive credit ±or these multiple-choice problems. Note that depending on method you use, some simplifcation may be required to fnd the correct equivalent choice. (a)
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This note was uploaded on 05/03/2008 for the course MATH 1081 taught by Professor Johanson during the Spring '08 term at Colorado.

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061Exam2asoln - EXAM 2 Section xxx March 2 2006 NAME Note...

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