ISMCh01[2]

ISMCh01[2] - CHAPTER 1 MEASUREMENT AND PROBLEM SOLVING...

This preview shows pages 1–3. Sign up to view the full content.

CHAPTER 1 MEASUREMENT AND PROBLEM SOLVING Remind students that their answers to odd-numbered exercises may be slightly different from those given here because of rounding. Refer to Problem-Solving Hint: The "Correct" Answer in Chapter 1. 1. (b). 2. (c). 3. (c). 4. (a) Since 1 gal = 3.785 L, 300 L = (300 L) × = 79.3 gal. . (b) Since 1 in. = 2.54 cm, 225 cm = (225 cm) × = 88.6 in. = 7 ft 5 in. . . (c) Since 1 m = 3.28 ft, 120 m 2 = (120 m 2 ) × 3.28 ft 1 m 2 = 1.29 × 10 3 ft 2 . . 5. (b) 6. Since 1 in. = 2.54 cm, 3 cm = (3 cm) × = 1.2 in. That would have been a huge lady bug. . Since 1 kg is equivalent to 2.2 lb., 10 kg = (10 kg) × =22 lb. Salmon are quite large. 7. The decimal system (base 10) has a dime worth 10¢ and a dollar worth 10 dimes, or 100¢. By analogy, a duodecimal system would have a dime worth 12¢ and a dollar worth 12 “dimes,” or \$1.44 in decimal dollars. Then a penny would be of a dollar. 8. (a) Different ounces are used for volume and weight measurements. 16 oz = 1 pt is a volume measure and 16 oz = 1 lb. is a weight measure. (b) Two different pound units are used. Avoirdupois lb. = 16 oz‚ troy lb. = 12 oz. 9. That is because 1 nautical mile = 6076 ft = 1.15 mi. A nautical mile is larger than a (statute) mile. 10. (d). 11. (d). 12. , it only tells if the equation is dimensionally correct. 13. (c). 14. Dividing something is equivalent to multiplying by the reciprocal. m/s ÷ s = × = . Chapter 1 Measurement and Problem Solving 1

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
15. Dimensional analysis uses the fundamental dimensions of physical quantities such as, length ([L]), mass ([M]), and time ([T]). Unit analysis uses a specific system of units. For example, if the mks system is used, then meter (m), kilogram (kg), and second (s) are used in unit analysis. 16. [L] = [L] + × [T] = [L] + [L]. 17. (d). 18. [T] = = = [T]. The equation is dimensionally correct. 19. m 2 = (m) 2 = m 2 . 20. , since [m 3 ] = [m] 3 = [m 3 ]. 21. . V = 4 π r 3 /3 = 4 π (8 r 3 )/24 = 4 π (2 r ) 3 /24 = π d 3 /6. So it should be . 22. x = g = . So the units of g are . 23. , because m/s m/s – (m/s 2 )(s) 2 = m/s – m. 24. Since ρ = , the unit of mass is kg, and the unit of volume is m 3 , the unit of is equal to = . 25. , because [L 2 ] = [L]([L] + [L]) = [L 2 ] + [L 2 ]. 26. , because m/s = = = m/s. 27.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 8

ISMCh01[2] - CHAPTER 1 MEASUREMENT AND PROBLEM SOLVING...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online