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Chem Lab 10

# Chem Lab 10 - a 1/volume value of 0(mL The mathematical...

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74.85 18 71.77 19 67.61 20 64.58 13 97.29 14 90.71 15 85.07 16 79.87 17 74.85 18 71.77 19 67.61 20 64.58 150.73 9 134.47 10 122.26 11 113.36 12 103.49 13 97.29 14 90.71 15 85.07 16 79.87 17 74.85 18 71.77 19 67.61 20 64.58 .0556 71.77 .0526 67.61 .0500 64.58 13 97.29 14 90.71 15 85.07 16 79.87 17 74.85 18 71.77 19 67.61 20 64.58 .1111 134.47 .1000 122.26 .0909 113.36 .0833 103.49 13 97.29 14 90.71 15 85.07 16 79.87 17 74.85 18 71.77 19 67.61 20 64.58 Mike Geddes E10: Gas Behavior Lab Partners – Kate Gernert

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The kind of curve which results from the data is an inversely proportional polynomial curve. The data I had had a value of .994, which shows that it accurately fits within the given formula of the regression line of the data. This line does not pass through the origin. Instead, by looking at the equation of the line of regression, it can be determined that when x=0, y=25.44. At the origin, it would mean that there is 0 pressure (kPa) and
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Unformatted text preview: a 1/volume value of 0 (mL). The mathematical relationship between pressure and volume is based off of the combined gas law. To maintain a constant pressure, one must change the pressure or volume in such a way that it is still proportionately equal. Example PV/T = PV/T 1atm(1L)/298K = 2atm(.5L)/298K P = 0.308(T) + 10.66 This line will not pass through the origin. Its y-intercept will be at (0,10.66). The slope of the line is .308 kPa per degree K, which can be calculated by dividing the Pressure by ∆ Temperature over the same interval. ∆ P = 0.308(T) + 10.66-10.66 = 0.308(T)-34.61K = the temperature at which P = 0 Pressure (kPa) Temperature (K) 95.16 274.74 100.07 289.95 101.04 293.15 105.78 308.15 110.05 323.15...
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