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Unformatted text preview: are measured in miles. Since and are decreasing we take the derivatives to be negative and so we are given mi/h and mi/h. To find we use the Pythagorean Theorem, namely and differentiate with respect to time . We have and by solving for we have Now when mi and mi we have mi and so 2. Integrate: (find the antiderivative) dx x x x x x ) tan sec 4 cos 6 sec 2 ( 2 +--∫ Solution C x x x x + +--sec 4 sin 6 tan 2 3 2 2 3...
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This note was uploaded on 05/06/2008 for the course MATH 201 taught by Professor Chuckrow during the Spring '08 term at CUNY City.
- Spring '08