This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: are measured in miles. Since and are decreasing we take the derivatives to be negative and so we are given mi/h and mi/h. To find we use the Pythagorean Theorem, namely and differentiate with respect to time . We have and by solving for we have Now when mi and mi we have mi and so 2. Integrate: (find the antiderivative) dx x x x x x ) tan sec 4 cos 6 sec 2 ( 2 +∫ Solution C x x x x + +sec 4 sin 6 tan 2 3 2 2 3...
View
Full Document
 Spring '08
 CHUCKROW
 Calculus, Geometry, Pythagorean Theorem, Car, Euclidean space

Click to edit the document details