ea1 8th assignment 11-29

ea1 8th assignment 11-29 - Neal Bhatia EA1- Nocedal...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Neal Bhatia EA1- Nocedal 11/29/07 Assignment #8 1. #4. Vector u=[2,1] is in H. Scalar c=-5 multiplied by u yields a vector= [-10,-5], which is not in H. #8. [-3 -2  0   1  ~[ 1     0     2    -5         0   2  -6  14    0    -1     -3    7         6   3  3   -9]    0    0      0     0]                                                     Since the augmented matrix is consistent, Ax=p has a solution, so p is in Col A.  #10.  [-3    -2     0     0    0     2    -6     0    6     3     5     0] ~    [ 1     0     0     0      0     1     0     0      0     0     1     0] Because the reduced row echelon form of [A,0] is as shown above, the only solution for Ax=0 is  the zero vector, and therefore u is not in nul A. #14.  [1     2     3     0   4     5     7     0   -5    -1     0     0    2     7    11     0] ~ [1.0000         0   -0.3333            0          0    1.0000    1.6667          0          0         0            0                   0
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 5

ea1 8th assignment 11-29 - Neal Bhatia EA1- Nocedal...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online