Chem Lecture 4

# Chem Lecture 4 - Empirical formula problems involving mol...

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Sheet1 Page 1 Empirical formula problems involving %, mol, grams A) Calculate the empirical formula of a compound containing .103 mol Carbon, .515 mol Hydrogen, and .309 Oxygen. Divide all numbers by smallest available number listed in problem -i.e: .515/.103, .309/.103, etc B) Calculate the empirical formula of a compound containing 4.86g Magnesium, and .403g of Hydrogen Find mol by dividing grams by atomic weight of individual elements Divide number of mols by smallest available number --- How to calculate Molecular Formula: -Calculate the molecular formula of a compound of empirical formula SNH and molar mass 188.35g/mol N = Molar mass / empirical formula mass N = Empirical formula mass (32.07 + 14.01 + 1.008) = 47.09 N = 188.35 / 47.09 = 4.000 Molecular formula = empirical formula x N Molecular Formula = (SNH) x4 = S4N4H4 --- Find the molecular formula of this compound: -Molar mass of a compound is 108.96 g/mol -Empirical formula: C2H5Br --- Steps for calculations: 1. Balance equation, if necessary

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Chem Lecture 4 - Empirical formula problems involving mol...

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