Chem Lecture 7

Chem Lecture 7 - Standard Solution: A solution whose...

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Sheet1 Page 1 Standard Solution: A solution whose concentration is accurately known Stock Solution: Concentrated form of a solution Dilution: Addition of a solvent (usually water) to a stock solution. The concentration of the stock solution will decrease Mol of solute before dilution = mol of solute after dilution Molarity = Mol of solute / Vol (L) Molarity x Vol = Mol A) 60.0 mL of water was added to 30.0mL of 0.450M HCl solution. Calculate the concentration of the diluted solution V(c) = 30.0mL M(c) = .450M HCl V(d) = 60.0 M(d) = ? B) What volume of 18.0M NH3 solution is required to prepare 500.0mL of a 2.00M NH3 solution? V(olume)(d(ilute)) = 500.00mL Molar(d) = 2.00M M(c(oncentrate) = 18.00 V(c) = ??? 18.00 x Vc = 2.00M x 500.00mL Vc = 2.00M x 500.00mL / 18.00M --- Precipitation Reactions -Reaction in which an insoluble substance (precipitate) is formed in solution e.g. ->2Kl(aq) + Pb(NO3)2(aq) -> PbI2(s) + 2KNO3(aq) --- Silver Nitrate (aq) + Ammonium Chloride (aq) -> Silver Chloride (s) + Ammonium Nitrate (aq)
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Chem Lecture 7 - Standard Solution: A solution whose...

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