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Unformatted text preview: Homework 5 Step 1, formulas or related concepts. In serial: In parallel: Step 2, known quantities. Step 3, direct application of the formulas/concept or the condition to form an equation. , , 1 1 a) + = 5.96( F ) 1 1 1 20 + +6 15 3 1 1 U 20 F + U (15 F,3 F,6 F) = 15.0 for 20 F : 20 U 20 F = U 20 F = 4.47(V ) 1 1 1 Q20 F = 4.47 6 = 8.94 5 (C ) 20 10 10 U (15 F,3 F,6 F) = 10.53(V ) + + 6 U (15 F,3 F,6 F) 15 3 b)  for 6 F : Q6 F = 10.53 6 10=6 6.32 105 (C ) U U 15 F + U 3 F = 10.53V 15 F = 1.76(V ) for 15 F: Q5 F = 1.76 6 = 2.63 5 (C ) 15 10 10 U15 F 15 = U 3 F 3 U 3 F 8.77(V ) = for 3 F : Q3 F = Q5 F = 2.63 105 (C ) Step 4, vector involved? No. Step 5, unit in the final answer correct? Answered all were asked? Unit is F and C , all questions answered.
2 Homework 2 Step 1, formulas or related concepts. In serial: In parallel:
Step 2, known quantities. , C1=5.00F, C2=10.00F, and C3=2.00F.
Step 3, direct application of the formulas/concept or the condition to form an equation.
1 1 1 1 1 1 1 260 1 = 6.05( F ) + + + + 2 + ( 10 + 10 ) = 5 10 10 5 43 1 Step 4, vector involved? No. Step 5, unit in the final answer correct? Answered all were asked? Unit of capacity F. All questions answered. 3 Homework 2 Step 1, formulas or related concepts. Step 2, known quantities. , 100 V power supply. Step 3, direct application of the formulas/concept or the condition to form an equation. a) 1 U1 =a 25 106 1002 = 0.125( J ) f 2 1 U 2 =a 5 106 1002 = 0.025( J ) f 2
4 b) V 1 + V2 = 100(V ) 25V1 = 5V2 V 1 = 16.67(V ) V 2 = 83.33(V ) 1 U1 = 25 106 16.67 2 =C 3.47 103 ( J ) 2 1 U 2 = 5 106 83.332 =C 1.74 102 ( J ) 2 U total = 3.47 103 + 1.74 102 =C 2.09 102 ( J )
Step 4, vector involved? No Step 5, unit in the final answer correct? Answered all were asked? Unit of Energy is J. All questions answered. 5 Homework 2 Step 1, formulas or related concepts. 2 Step 2, known quantities. U = P Step 3, direct application of the formulas/concept or the condition to form an equation. a) U 2 1102 R= = = 24.2() P 500 5 24.2 108 RA 2 l= = = 3.17(m) 6 1.5 10
6 2 b) R = R0 + ( T  T0 ) 24.2 + 0.4 103 ( 1200  20 ) 35.62() 1 = 1 = 1102 P= = 339.7(W ) 35.62 Step 4, vector involved? No Step 5, unit in the final answer correct? Answered all were asked?
YES. 7 Step 1, formulas or related concepts. Step 2, known quantities. Step 3, direct application of the formulas/concept or the condition to form an equation. I= J= V R I V V = = A Rr 2 l After Stretching, the length is 4 times than the original one, so the cross section is to the original one.
8 Rstretched = I stretched = J stretched = 4l l = 16 = 16 R 1 A 4 A V 16 R I stretched V V = = 1 4 Rr 2 4l A 4 Step 4, vector involved? No. Step 5, unit in the final answer correct? Answered all were asked? Yes. All questions answered. 9 ...
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This note was uploaded on 05/06/2008 for the course PHYS 1304 taught by Professor Ye during the Spring '08 term at SMU.
 Spring '08
 Ye
 Magnetism, Work

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