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School of Chemical and BiomedicalEngineeringDivision of Chemical and BiomolecularEngineeringCH3802CE5: FermentationName:Jaideep Singh SoodanMatric Number: U1922749LGroup: LAA33Date: 14/10/2021
Objectives1.To analyse the process of yeast fermentation and qualify its efficiency through cellgrowth, glucose consumption and ethanol production at varying temperatures.2.To compare the efficacy of different equipment in quantifying glucose and ethanollevels in fermentation broth samples.3.To understand the effect of temperature control on the fermentation process.Results[Our group worked on T = 25oC i.e. Control Group]1.Cell Concentration Tablea.T = 25oC (Control Group)Table 1: Cell Concentration Data for Control Group (T= 25oC)Time (hours)OD600ReadingDilution FactorApparent CellConcentration(g/100g)[FromCalibrationCurve]Actual CellConcentration(g/100g)00.46100.042369070.4236907210.481100.047104520.4710451820.496100.050672060.5067205630.527100.058551090.5855109440.597100.079001070.7900107450.669100.104201891.04201885Sample CalculationFrom reference [1], the calibration curve for standard yeast cell concentration (dryweight of yeast per 100g of sample) versus Optical Density (OD) of a given sample isgiven as:Ccell[g/100g] = -0.0055 + (0.0282*OD) + (0.0812*OD2) + (0.182*OD3)At t = 0 hours,Ccell[g/100g] = -0.0055 + (0.0282*0.46) + (0.0812*0.462) + (0.182*0.463)Ccell= 0.04237However, this concentration is for diluted sample (2). Following the dilution law,
C1V1= C2V2Hence,C1 = C2 ∗V2V1= C2 ∗ Dilution Factor𝐂? = ?. ????? ∗ ?? = ?. ????b.T = 35oCTable 2: Cell Concentration Data for 35oCTime (hours)OD600ReadingDilution FactorApparent CellConcentration(g/100g)[FromCalibrationCurve]Actual CellConcentration(g/100g)00.473100.0452650.452710.479100.0466410.466420.563100.0685930.685930.624100.0879350.879340.622100.0872520.872550.771100.1479241.47922.Sugar ContentTable 3: Sugar Content Data for both temperature groupsSub-group 1 (Control Group 25oC)Sub-group 2 (35°C)TimeSugar Content (0Plato)TimeSugar Content (0Plato)(h)RefractometerDMA 35Alex 500(h)RefractometerDMA 35Alex 50007.56.56.5307.16.36.317.46.36.4416.96.16.1327.26.16.2126.65.65.6336.85.85.8536.25.15.0446.75.45.4545.84.44.4256.44.84.8755.43.93.91
3.Alcohol Content calculated from densitiesTable 4: Measured values of density from DMA35 and Alex500Sub-group 1 (Control Group25oC)Sub-group 2 (35°C)TimeDensity (g/ml)Density (g/ml)(h)DMA35Alex 500DMA35Alex 50001.02231.02391.02131.023011.02171.02361.02041.022421.02081.02271.01841.020431.01971.02121.01521.018041.01811.01961.01371.015551.01581.01731.01161.0135Table 5: Calculated values of alcohol content using density valuesSample Calculation [Alex500 Subgroup1 t= 1 hour]𝐴𝑣𝑣= ? × (?? − ??)Assuming a linear relationship between f and (OG-PG), we linearly interpolate across a rangeas follows:0.125 < ? < 0.135and6.9 < (?? − ??) < 100.7Hence,? = ?(?? − ??) + 𝐶Sub-group 1 (Control Group 25oC)Sub-group 2 (35°C)TimeAlcohol Content (v/v%)TimeAlcohol Content (v/v%)(h)DMA35(Calculated)Alex 500(Calculated)Alex 500(Measured)(h)DMA35(Calculated)Alex 500(Calculated)Alex 500(Measured)00.0000.0000.360000.4610.0750.0370.3210.110.070.5620.1870.1490.420.360.320.7230.3240.3360.5630.760.621.0240.5240.5360.8240.950.941.3450.8120.8251.1851.221.191.6
Applying a linear trendline on Excel,Figure 1: Linear Trendline between f and (OG-PG)From the trendline,m = 0.0001 and C = 0.1243For Alex500 at t = 1hour,OG = 1.0239 * 1000 = 1023.9PG = 1.0236 * 1000 = 1023.6Hence,f = (0.0001)*(1023.9-1023.6) + 0.1243 = 0.12433Therefore,𝑨𝒗𝒗= ?. ????? × (????. 𝟗 − ????. ?) = ?. ???

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Alex 500 25deg