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Unformatted text preview: Step1 of1 A The formula to find the sum of two vectors A and B is: R = A2 + .15?2 +2ABcosG Here, R is the magnitude of resultant vector and a be the angle between two vectors A and B.
Assume A and B are the two pulls whose magnitudes are equal. Let x be the magnitudes of the each pull. That is
A = x
B = x
Substitute, 12.8 N for Fl, xfor A, xfor B and 64°for a, 12.8 N = ‘fo +82 + 2(x)(x)cos64° Take square both sides, (12.8 N)2 = 2.»:2 + 2;:2 (0.438)
163.84 N2 = 2.876 x2 2 _ 163.84 N2 2.876
x = 7.55 N Thus, the pulls are 7.55 N . x Comment Step 4 of4 A E: =Rx 31
= 0(158.2 N)
=153.2 N E, = 132.5 Nl69.7 N
= —37.2 N Elbow force, E = JE: +E’2 = (153.2 N)’ +(37.2 N)2
= 162.5 N Angle made by elbow force: a=tan"§l
E 3
_ and 37.2 N
153.2 N = ( below the horizontal) Comment ...
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 Spring '09
 Macdonald

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