oldhw21_s - oldhomewk 21 YOO, HEE Due: Apr 1 2008, 4:00 am...

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Unformatted text preview: oldhomewk 21 YOO, HEE Due: Apr 1 2008, 4:00 am 1 Question 1, chap 10, sect 1. part 1 of 1 10 points An object having an initial momentum that may be represented by the vector be- low strikes an object that is initially at rest. Which of the following sets of vectors may represent the momenta of the two objects af- ter the collision? Note carefully: The original vector above and the following vectors are all drawn to the same length scale. 1. 2. 3. correct 4. 5. 6. 7. Explanation: There is no external force for the two-object system, so the total momentum is a constant. From the choices, applying the vector sum- mation for the momenta of the two objects, we can easily identify the correct choice. The figure below shows the sum of the x- and y-components of the vectors which repre- sent the correct answer. initial momentum The horizontal vectors add to be the same length as the vector presented in the question. The vertical vectors cancel, as expected, since there is no vertical momentum. Question 2, chap 10, sect 99. part 1 of 1 10 points The bird perched on the swing in the figure has a mass of 40 g, and the base of the swing has a mass of 124 g. Assume that the swing and the bird are originally at rest and that the bird then takes off horizontally at 2 . 98 m / s. The acceleration of gravity is 9 . 8 m / s 2 . oldhomewk 21 YOO, HEE Due: Apr 1 2008, 4:00 am 2 If the base can swing freely (without fric- tion) around the pivot, how high will the base of the swing rise above its original level? Correct answer: 0 . 0471469 m (tolerance 1 %). Explanation: Let : m b = 40 g , m s = 124 g , and v b = 2 . 98 m / s . By momentum conservation we can find the speed of the swing when the bird takes off v s = m b m s v b = 40 g 124 g 2 . 98 m / s = 0 . 96129 m / s . Then, because of energy conservation, the height the swing can reach is h = v 2 s 2 g = (0 . 96129 m / s) 2 2 (9 . 8 m / s 2 ) = . 0471469 m . Question 3, chap 10, sect 1. part 1 of 1 10 points A uranium nucleus 238 U may stay in one piece for billions of years, but sooner or later it decays into an particle of mass 6 . 64 10 27 kg and 234 Th nucleus of mass 3 . 88 10 25 kg, and the decay process it- self is extremely fast (it takes about 10 20 s). Suppose the uranium nucleus was at rest just before the decay. If the particle is emitted at a speed of 2 . 43 10 7 m / s, what would be the recoil speed of the thorium nucleus? Correct answer: 415856 m / s (tolerance 1 %)....
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This note was uploaded on 05/04/2008 for the course PHY 303K taught by Professor Turner during the Spring '08 term at University of Texas at Austin.

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oldhw21_s - oldhomewk 21 YOO, HEE Due: Apr 1 2008, 4:00 am...

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