# HW #4 - Chapter 9 p.382#60-64 68-70 p.382#60 a H 0 = 16 H a...

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Chapter 9 p.382 #60-64, 68-70 p.382 #60 a). b). z 2.19 p-value 0.03 c). z -1.23 p-value 0.22 continue operation d). part b part c z = -1.23 Reach the same conclusion #61 a). b). x 935 z(a/2) 25 x + z 960 x - z 910 c). d). z 2.75 p-value 0.0060 #62 a). b). z 2.60 p-value 0 c). #63 μ 250,000 H 0 : μ = 16 H a : μ 16 .0286 .05 reject H 0 .2186 .05 do not reject H 0 Reject H 0 if z ≤ -z α/2 OR z ≥ z α/2 2.19 1.96 reject H 0 do not reject H 0 H 0 : μ = 900 H a : μ 900 reject H 0 because 900 does not fall within the interval (910 to 960). H 0 : μ \$119,155 H a : μ > \$119,155 .0047 .01 reject H 0

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20 x 266,000 s 24,000 t 2.98 degree of freedom 19 p-value less than .005 #64 μ 6,000 n 32 x 5,812 s 1140 t -0.93 degree of freedom 31 p-value .20 to .40 #68 a). b). 0.64 c). 0.05 z 2.8 p-value 0 #69 a). 0.6667 b). p 0.6502 c). 0.0202 z -0.8171 p-value 0.41 d). H 0 : μ 250,000 H a : μ > 250,000 .005 .01 reject H 0 .20 .05 do not reject H 0 H 0 : p .50 H a : p > .50 σ p .0026
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## This note was uploaded on 05/11/2008 for the course IS 310 taught by Professor Sun during the Spring '08 term at CSU Long Beach.

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HW #4 - Chapter 9 p.382#60-64 68-70 p.382#60 a H 0 = 16 H a...

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