MATH-1P98-Webwork-3-Attempt-4

# MATH-1P98-Webwork-3-Attempt-4 - Aanjaneya Sood Assignment...

This preview shows pages 1–2. Sign up to view the full content.

Aanjaneya Sood MATH1P98D02FW2016 Assignment WeBWorK Assignment 3 due 10/30/2016 at 02:31am EDT Problem 1. 6. (1 pt) Find the value of the standard normal random variable z , called z 0 such that: (a) P ( z z 0 ) = 0 . 5865 z 0 = (b) P ( - z 0 z z 0 ) = 0 . 8954 z 0 = (c) P ( - z 0 z z 0 ) = 0 . 2748 z 0 = (d) P ( z z 0 ) = 0 . 143 z 0 = (e) P ( - z 0 z 0 ) = 0 . 372 z 0 = (f) P ( - 2 . 07 z z 0 ) = 0 . 5544 z 0 = Answer(s) submitted: (incorrect) Correct Answers: 0.218550777026199 1.62295043870524 0.351517694667278 1.06693763219277 1.13589622116733 0.185547024908919 Problem 2. 10. (1 pt) A study on the length of time a person brushes their teeth is conducted on a large population of adults. The mean brushing time is μ and the standard deviation is σ . A simple random sam- ple of 240 adults is considered. (NOTE: For the following problems enter: GREATER THAN ”, ” EQUAL TO ”, ” LESS THAN ”, or ” NOT ENOUGH INFORMATION ”, without the quotes.) (a) The mean of the sampling distribution is the mean of the population. (b) The standard deviation of the sampling distribution is the standard deviation of the population. Answer(s) submitted: (incorrect) Correct Answers: EQUAL TO LESS THAN Problem 3. 7. (1 pt)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern