Tutorial 7 Solution(1) - ELEG4503 Modern Communication...

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ELEG4503 Modern Communication System Self-Practice: Tutorial 7 October 20, 2016 1 Line Codes (20%) (a) What is the logic bit stream for the following bipolar NRZ-L code diagram? (5%) 1 +A -A 3×10 -3 sec (b) If the bit error probability of detection is not larger than 3 . 167 × 10 - 5 , the power spectral density η is 2 × 10 - 4 W/Hz and the bit duration time is the same as the above bipolar NRZ-L code, what’s the minimum received signal power? (15%) You may need Q (3) = 1 . 300 × 10 - 3 Q (4) = 3 . 167 × 10 - 5 Q (5) = 2 . 867 × 10 - 7 Q (6) = 9 . 866 × 10 - 10 Q (7) = 1 . 280 × 10 - 12 Answer: (a) 1 101101 (b) First, we find that the bit duration time is 5 × 10 - 4 s. Based on Nyquist criterion, we have 2 B 1 T b (1) 1
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Then, we derive B 1 kHz. N = ηB = 2 × 10 - 3 B Since Q r S N ! 3 . 17 × 10 - 5 r S N 4 (2) we have S = 3 . 2 × 10 - 3 B 3 . 2 W .
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