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Unformatted text preview: Home ( a digitalveilummactecol Homework: Review for Exam 3
Math 01B07, The population meanaml standard deviation are given below. Fini the Inquirer} probability anédﬂermine whether the given sample mean wouli be
considered unusnal. Homework,
Qu ium a Tats Fora sample ofn=62Llindthe probability ofa samplemanbeinglessthan249ﬂn=25 andcr=1JI @mmammiewpage : ofthe standardnormaltable, II 1" Text )
D ea 2 (iclicktheicontoviewpageloftheslami'ndnormaltable. Gradeboolr
Since the sample size is greater than 30, the cranial limit theorem unbe used to conclude that the distribution of sample means is approximately
Study Plan normal, where the mean ofthe sample mms n; is equalto the population mean]: andthe standard deviation ofthe sample means (I; is agnal to
(optional) the population standard deviation (1 dividedby the square root ofthe sample size n, as shown by the fmlﬂas below. = 5 Tools for Succﬁs
n; =11 and a; 7 ll; Multimedia Library
As givm inthe problem statmnent, 11:25, so n;=25 Now ﬁndo; Substitute o= 1 37 andn=62 into the formula for o; and upli'l'y, Purchase Options F Courge Tools 0'
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1,37 #5 0.174 Qummn is complete. . Home _\ 7 _ _ _ _ _ ‘
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Math 01—307, The population manand standard deviation are given below, Find the required probability anddetermine whether the given sample mm would he
considered Imnsnal. Homework,
Quium a Tats Fora sample ofn=62Llindthe probability ofa samplemmlnbdnglessthan2493n=25 ando=l,37, aClicktheicontoviewpage z ofthe standardnormaltable. R d Text ».
’ ea 2 (iclicktheicontoviewpageloftheslanhrdnnrmaltable. Gradeboolr
Find the probability that the sample mmx will fallinthe givm intmal ofthe sampling distribution by transforming x to a ZrSCOIE um'ng the formula
Study Plan below.
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Purchase Options D Course Tools =5 0,57 Quwmn ‘5 complete. D n hﬂpsllwww MMILQWSIudenUPlayeIHumewmkm hommumd 25110954qu [ﬂ
( ‘0 mgualveuummmuol Kelly Gallegos 21 #151  ‘ » Review for Exam 3 Math 01307, The populatiunmeanaml slamlarddevialiunaIe givenbelﬂw. Fini lhe requiredpmbabiliiy arddeienuine Whelhel the given sample meanwoulibe
cunsideredlnnmial Fora sample ofn=61ﬁndlhepmbabilityofa samplemanbeing less lhan249i‘l'p=25 andcr=1,37, @cﬁckmemoviewpage 1 ofthe standaxdnm'mallahle,
@cnckmnmmvigwpagezomc standardnunnallahle. , x z= 0 x Study Plan
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The probability lhat lhe sample meanislessthan249 is quaint: PG<24,9) =P(z< *057), This pmbability corresponds tothe axes lo theleﬂof z= *057undenheslandaIdnotmaldislribmimToﬁndlheaiutotheleﬁofzusethestandaldnmmallahletoﬁndlheaiuthalcmespmdsto
z. Purchage Options ’ Courge Tools Note lhal dihetlechmlogymthe standaxdnm'mallahlecanbe usedluﬁndthisalubulfotthepmposesofthis explanation, wewilluselhelable,
Theaiu that conesponds to 2: *0 57inihe slandaidnormaltahleisolMl Thus,fma sample ofn=61lhepmhalrilityofa samplemeanbin'ng less lhan249ﬂu=25 an‘ch‘leisOlMﬂ, Tn de'lennine i‘l'a sample meanaf24.9i5 consi‘letedumlsualrecall lhal events wilha probability nilessthan 5% are consﬂemdunusual Queqmn l5 cnmplete. ﬂ Cut .
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ase v d Funnel Painte ammo a Review for Exam 3 Findthe pmbahilily andimetptel the [esulls Ifconveniem, use technnlngy to ﬁnd lhe probability, During a cenain week lhe mm price ofgasuline
was $2.714 pet gallpn. A tandem sample of 35 gas slaliuns is drawnfmm lhis pupulaliim Whal is lhe pmbabilitythallhe meanpricefmthe sample
was betwem $2,693 and $2,724 that week? Assume a = $0,049, @cnckmnmmvigwpage 1 ofthe standardnunnallahle.
@MMkmtompagezofme standaxdnm'mallahle, The pmbability lhat a sample mean lies between $2.693 ani$2.724 canbe foun‘l using the Cenhal Limil Themem. The CenhalljmitTheorem 1, Ifsamples ofn'zenwheren230,a1edtawnﬁomanypuplﬂainnwithammp
amia slaniatddevialiuno,thenlhe samplingdisln'huliunafsample means
appmximalesa mmaldisuilyuliun The grealenhe sample she, lhe bell: the
appmximatkm
2,Thesampﬁngdi5uﬁmﬁonofsamplemunshasammequalmthepupulaﬁm
mean
3,Thesamphngdishibuﬁmofsamplemeanshasaslandasddeﬁaﬁmeqmllolhe
pupulalion slandaIddevialimdihkiedbythe squaIe (out ofn Aocmding m theCemIalLimil Themem, lhe distributionoflhe sample means willhe appmximately normal Determineihe palamelets oflhe
samphngdiskibuliunFirsLiindlhemeanushgthefacllhalthemeanoflhe samplingdiskibuliunislhesameaslhepupulaﬁunmean n; =2714 Now ﬁndthe slandajd deviation ofthe dislrihulinnof sample means, munding In ﬁve decimalplaces, me the Casual Limit Theorem, the sampling Quwmn ls cnmplete. fi ‘adlgltalvellum nextecol https wwwmattullLom/Student/FlayelHomewo asp homeworldd 3.511095495tquestlonl falseatd MIETStEenterwm ethtromPlayerChEl Kelly Gallegos 2/24115 1"  . » Homework: Review for Exam 3 Find the probability and interpret the results. liconvem'ent, use technology to ﬁnd the probability. During a certain week the mean price ofgasoline
was $1.714 per gallon. A random sample of 35 gas stations is drawn from this population “that is the probability that the mean price for the sample
was betwem $2,693 and $2,724 that week? Assume o =$0.049. Homework,
Qn iuﬁ a Tats @ Click the icon to View page 1 ofthe standard normal table. > Read eText @ Click the icon to View page 2 ofthe standard normal table. Now ﬁnd the standard deviation ol'the distribution of sample meam, rounding to ﬁve decimal places. From the Central Limit Theorem, the sampling “New" distribution or sample means has a standard deviation equal to the population standard deviation divided by the square root orn Study Plan _ (optional) o e L =
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0.00828 Multimedia Library Pn rcllage Options With these values for the mean and standard deviation the z—score corresponding to a sample mean of2.693 can be folmd, rounding to two decimal F Course Tools places. 5;
2.693 — 2.714
0 0087.8 Questlnn l5 complete. ( ‘6 dlgltnlvellnmneneeol MostVtsited Magneto Kelly Galleg 5 2/24,:‘15 1i
Homework: Review for Exam 3 Find the probability and interpret the results. lfconvenient, use technology to ﬁnd the probability. During a certain week the mm price ofgasoline
was $2.714 per gallon. A random sample of 35 gas stations is drawn from this population What is the probability that the mean price for the sample
was betwetm $2,693 and $2,724 that week? Assume o =$0.049. Homework,
Qnium n Tats @ Click the icon to View page 1 ofthe standard normal table.
Q Click the icon to View page 2'. ofthe standard normal table. ) Read eText
0.0003 Gradeboolr ’5 i 2.54
Study Plan _
(optional) While m'thm' technology or a normal distribution table can be used to answer this question, for the purposes ofthis explanation we will use a table = To ﬁnd the probability that i is less than 2.693, ﬁnd the value on the table that corresponds to z: r254.
Tools for Snccﬁs = < 7254
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Now ﬁnd the ZiSCm'E for a sample mean of 2.724, rolnxﬁng to two decimal places. D Course Tools 1724* 2.714
0.00l2l
=5 1.21 Use the standard normal table to ﬁnd the probability that i is less than 2.724. anlnn ls complete. ...
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 Spring '12
 RobertFrancisRitchie
 Geography

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