problem43_04

Problem43_04 - protons b m.48 4 MHz 9 66 = = = ∆ = f c h E f

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43.4: a) As in Example 43.2, eV. 10 77 . 2 ) T 30 . 2 )( T eV 10 15245 . 3 )( 9130 . 1 ( 2 7 8 - - × = × = E Since S N and are in opposite directions for a neutron, the antiparallel configuration is lower energy. This result is smaller than but comparable to that found in the example for
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Unformatted text preview: protons. b) m. .48 4 λ MHz, 9 . 66 = = = ∆ = f c h E f...
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This note was uploaded on 05/12/2008 for the course PHYS 262 taught by Professor Dougherty during the Spring '08 term at Lafayette.

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