problem43_09

# problem43_09 - ⇒ E 11 10 11 MeV 69 23 2-MeV 76.68 B = ⇒...

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43.9: a) For B 11 5 the mass defect is: ) 5 6 5 11 5 e n p B M( m m m m - + + = u) MeV u)(931.5 081815 . 0 ( energy binding The u 0.081815 u 009305 . 11 ) u 000549 . 0 ( 5 ) u 008665 . 1 ( 6 ) u 007277 . 1 ( 5 B = = - + + = E MeV 76.21 = b) From Eq. (43.11): A Z A C A Z Z C A C A C E 2 4 3 2 1 B ) 2 ( ) 1 ( 3 1 3 2 - - - - - = and there is no fifth term since Z is odd and A is even. 3 1 3 2 11 ) 4 ( 5 ) MeV (0.7100 MeV)(11) 80 . 17 ( 11 ) MeV 75 . 15 ( B - - =
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Unformatted text preview: ⇒ E ) 11 ( ) 10 11 ( ) MeV 69 . 23 ( 2--MeV. 76.68 B = ⇒ E So the percentage difference is % 62 . 100 MeV 76.21 MeV 76.21 MeV 76.68 = ×-Eq. (43.11) has a greater percentage accuracy for Ni. 62...
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## This note was uploaded on 05/12/2008 for the course PHYS 262 taught by Professor Dougherty during the Spring '08 term at Lafayette.

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