problem43_10

problem43_10 - is odd making the pairing term zero This...

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43.10: a) = - + = - + u 62.929601 u 5) 29(1.00782 u 5) 34(1.00866 29 34 Cu H n m m m and u MeV 931.5 (using nucleon per MeV 8.75 or MeV, 551 is which u, 0.592 ). nucleons 63 b) In Eq. (43.11), Z = 29 and N = 34, so the fifth term is zero. The predicted binding energy is 3 1 3 2 ) 63 ( ) 28 )( 29 ( ) MeV (0.7100 MeV)(63) 80 . 17 ( ) 63 )( MeV 75 . 15 ( B - - = E MeV. 556 (63) (5) MeV) 69 . 23 ( 2 = - (The fifth term is zero since the number of neutrons is even while the number of protons
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Unformatted text preview: is odd, making the pairing term zero.) This result differs from the binding energy found from the mass deficit by 0.86%, a very good agreement comparable to that found in Example 43.4....
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