problem43_21

problem43_21 - 43.21: For 14 C, T1 2 = 5730 y - ( ln 2 ) t...

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Unformatted text preview: 43.21: For 14 C, T1 2 = 5730 y - ( ln 2 ) t T1 2 A = A0e - t ; = ln 2 T 1 2 so A = A0e ; A0 = 180.0 decays min a) t = 1000 y, A = 159 decays min b) t = 50,000 y, A = 0.43 decays min ...
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This note was uploaded on 05/12/2008 for the course PHYS 262 taught by Professor Dougherty during the Spring '08 term at Lafayette.

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