problem43_23

problem43_23 - 3 43.23: a) 3 H -0 e+ 2 He 1 1 - t b) N = N...

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Unformatted text preview: 3 43.23: a) 3 H -0 e+ 2 He 1 1 - t b) N = N 0e , N = 0.100 N 0 and = (ln 2) T1 2 0.100 = e - t ( ln 2 ) T1 2 ; - t (ln 2) T1 2 = ln (0.100); t= - ln(0.100)T1 2 ln 2 = 40.9 y ...
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This note was uploaded on 05/12/2008 for the course PHYS 262 taught by Professor Dougherty during the Spring '08 term at Lafayette.

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