problem43_26

problem43_26 - 43.26: dN = N dt ln 2 = = T 12 ln 2 s 3.15...

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Unformatted text preview: 43.26: dN = N dt ln 2 = = T 12 ln 2 s 3.15 10 7 1620 yr 1yr = 1.36 10 -11 s -1 6.022 10 23 atoms = 2.665 10 25 atoms N = 1 g 226 g dN dec = N = (2.665 10 25 )(1.36 10 -11 s -1 ) = 3.62 1010 dt s 10 = 3.62 10 Bq Convert to Ci: 1 Ci 3.62 1010 Bq 3.70 1010 Bq = 0.98 Ci ...
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This note was uploaded on 05/12/2008 for the course PHYS 262 taught by Professor Dougherty during the Spring '08 term at Lafayette.

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