problem43_28

problem43_28 - 43.28: a)Solving Eq. (43.19) for , ln 2 ln 2...

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Unformatted text preview: 43.28: a)Solving Eq. (43.19) for , ln 2 ln 2 = = = 4.17 10- 9 s -1. T1 2 (5.27 y) (365 days year)(24 hrs day) (3600 sec hr ) b) N = c) 3.60 10 -5 g m = = 3.61 1017. Au (60) (1.66 10 -24 g) dN = N = 1.51 109 Bq, which is d) 0.0408 Ci. The same calculation for radium, dt with larger A and longer half-life (lower ) gives T (5.27 yrs) (60) A -5 RA N Ra = Co N Co 1/2Co Co = 0.0408 Ci (1.600 yrs) (226) = 3.57 10 Ci. T 1/2Ra ARa ...
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