problem43_29

problem43_29 - 14 10 53 . 2 = N nuclei, and an eighth of...

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43.29: a) s decays 10 56 . 7 Bq 10 56 . 7 ) 0 ( 11 11 × = × = dt dN and . s 10 75 . 3 min) s 60 ( min) 8 . 30 ( 693 . 0 693 . 0 λ 1 4 2 1 - - × = = = T so nuclei. 10 2.02 s 10 3.75 s decays 10 7.56 ) 0 ( λ 1 ) 0 ( 15 1 4 11 × = × × = = - - dt dN N b) The number of nuclei left after one half-life is 15 10 01 . 1 2 ) 0 ( × = N nuclei, and the activity is half: . s decays 10 78 . 3 11 × = dt dN c) After three half lives (92.4 minutes) there is an eighth of the original amount
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Unformatted text preview: 14 10 53 . 2 = N nuclei, and an eighth of the activity: . s decays 10 45 . 9 10 = dt dN...
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This note was uploaded on 05/12/2008 for the course PHYS 262 taught by Professor Dougherty during the Spring '08 term at Lafayette.

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