problem43_38

problem43_38 - 43.38: a) From Table (43.3), the absorbed...

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43.38: a) From Table (43.3), the absorbed dose is 0.0900 rad. b) The energy absorbed is J; 10 1.35 kg) (0.150 ) kg J 10 (9.00 4 4 - - × = × each proton has energy J, 10 1.282 13 - × so the number absorbed is
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This note was uploaded on 05/12/2008 for the course PHYS 262 taught by Professor Dougherty during the Spring '08 term at Lafayette.

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