problem43_41

# problem43_41 - 3 1 15 2 Be H-× = × = × = × = r r So the...

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43.41: a) + = + = + = + + + 2 4 1 and 7 4 9 2 So He. X Be H 4 2 9 4 2 1 Z A A A Z Li. is X so , 3 7 3 = Z b) He) ( Li) ( Be) ( H) ( 4 2 7 3 9 4 2 1 M M M M m - - + = u. 10 678 . 7 u 002603 . 4 u 016003 . 7 u 012182 . 9 u 014102 . 2 3 - × = - - + = So MeV. 7.152 ) u MeV (931.5 u) 10 (7.678 ) ( 3 2 = × = = - c m E c) The threshold energy is taken to be the potential energy of the two reactants when they just “touch.” So we need to know their radii: m 10 2.5 (9) m) 10 2 . 1 ( m 10 1.5 (2) m) 10 2 . 1 ( 15 3 1 15
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Unformatted text preview: 3 1 15 2 Be H----× = × = × = × = r r So the centers’ separation is m 10 . 4 15-× = r Thus J 1 3 . 2 ) m 10 . 4 ( 4 C) 10 60 . 1 ( 4 4 1 13 15 2 19 Be H---× = × × = ⋅ = πε r q q πε U MeV. 1.4 eV 10 1.4 6 = × = ⇒ U...
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