problem43_47

Problem43_47 - Be He He 7 4 4 2 3 2 = × = M M M

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43.47: The energy liberated will be MeV. 586 . 1 ) v MeV (931.5 v) 7.016929 v 4.002603 v (3.016029
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Unformatted text preview: Be) ( ) He ( He) ( 7 4 4 2 3 2 = ×-+ =-+ M M M...
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This note was uploaded on 05/12/2008 for the course PHYS 262 taught by Professor Dougherty during the Spring '08 term at Lafayette.

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