problem43_60

problem43_60 - so , N . 10 20 . 1 s) 3600 hr 1 ( ) hr...

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43.60: a) A least-squares fit to log of the activity vs. time gives a slope of , hr 5995 . 0 λ 1 - = for a half-life of hr. 16 . 1 λ 2 ln = b) The initial activity is
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Unformatted text preview: so , N . 10 20 . 1 s) 3600 hr 1 ( ) hr (0.5995 Bq) 10 00 . 2 ( 8 1 4 = -N c) . 10 81 . 1 6 =-t e N...
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This note was uploaded on 05/12/2008 for the course PHYS 262 taught by Professor Dougherty during the Spring '08 term at Lafayette.

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