problem43_69

Problem43_69 - 43.69 For deuterium 1 e2 a U 4 0 r 4 b m 2 1(1.60 10 19 C 2 15 m(2)1 3 0 2(1.2 10 3 2 7.61 10 14 J 0.48 MeV 2M H M He mn 2(2.014102

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43.69: For deuterium: a) [ ] J 10 61 . 7 (2) m) 10 2 . 1 ( 2 4 C) 10 60 . 1 ( 4 1 14 3 1 15 0 2 19 2 0 - - - × = × × = = πε r e U MeV 0.48 = b) n 3 2 2 1 He) ( H) ( 2 m M M m - - = MeV 270 . 3 ) u MeV (931.5 u) 10 51 . 3 ( ) ( u 10 3.51 u 1.008665 u 3.016029 u) 014102 . 2 ( 2 3 2 3 = × = = × = - - = - - c m E J 10 5.231 13 - × = c) A mole of deuterium has 23 10 022 . 6 × molecules, so the energy per mole is
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This note was uploaded on 05/12/2008 for the course PHYS 262 taught by Professor Dougherty during the Spring '08 term at Lafayette.

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